z^2-24z+128=0

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Solution for z^2-24z+128=0 equation:


Simplifying
z2 + -24z + 128 = 0

Reorder the terms:
128 + -24z + z2 = 0

Solving
128 + -24z + z2 = 0

Solving for variable 'z'.

Factor a trinomial.
(8 + -1z)(16 + -1z) = 0

Subproblem 1

Set the factor '(8 + -1z)' equal to zero and attempt to solve: Simplifying 8 + -1z = 0 Solving 8 + -1z = 0 Move all terms containing z to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1z = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1z = 0 + -8 -1z = 0 + -8 Combine like terms: 0 + -8 = -8 -1z = -8 Divide each side by '-1'. z = 8 Simplifying z = 8

Subproblem 2

Set the factor '(16 + -1z)' equal to zero and attempt to solve: Simplifying 16 + -1z = 0 Solving 16 + -1z = 0 Move all terms containing z to the left, all other terms to the right. Add '-16' to each side of the equation. 16 + -16 + -1z = 0 + -16 Combine like terms: 16 + -16 = 0 0 + -1z = 0 + -16 -1z = 0 + -16 Combine like terms: 0 + -16 = -16 -1z = -16 Divide each side by '-1'. z = 16 Simplifying z = 16

Solution

z = {8, 16}

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